5-2/x+1/x^2=0

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Solution for 5-2/x+1/x^2=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^2)-(2/x)+5 = 0

1/(x^2)-2*x^-1+5 = 0

x^-2-2*x^-1+5 = 0

t_1 = x^-1

1*t_1^2-2*t_1^1+5 = 0

t_1^2-2*t_1+5 = 0

DELTA = (-2)^2-(1*4*5)

DELTA = -16

DELTA < 0

x belongs to the empty set

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